What is the derivative of f(x)=(-4x^2+9)^2 ?

The derivative of f(x)=(-4x^2+9)^2 is -16x(-4x^2+9)

What is the first derivative of f(x)=(-4x^2+9)^2 ?

The first derivative of f(x)=(-4x^2+9)^2 is -16x(-4x^2+9)

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derivative of

f (x) = (- 4 x^{2} + 9)^{2}

- 16 x (- 4 x^{2} + 9)

Solution steps

\frac{d}{d x} ((- 4 x^{2} + 9)^{2})

Apply the chain rule:

2 (- 4 x^{2} + 9) \frac{d}{d x} (- 4 x^{2} + 9)

= 2 (- 4 x^{2} + 9) \frac{d}{d x} (- 4 x^{2} + 9)

\frac{d}{d x} (- 4 x^{2} + 9) = - 8 x

= 2 (- 4 x^{2} + 9) (- 8 x)

Simplify

= - 16 x (- 4 x^{2} + 9)

\frac{d}{d x} (\frac{12}{x + 1})

x \to - 3 + lim (x)

\int \frac{x}{1 + 4 x ^{2}} d x

f (x) = \frac{2 x}{3}

y^{^{'}} = x (8 - y)

What is the derivative of f(x)=(-4x^2+9)^2 ?
The derivative of f(x)=(-4x^2+9)^2 is -16x(-4x^2+9)
What is the first derivative of f(x)=(-4x^2+9)^2 ?
The first derivative of f(x)=(-4x^2+9)^2 is -16x(-4x^2+9)