What is the derivative of x+c/x ?

The derivative of x+c/x is 1-c/(x^2)

What is the first derivative of x+c/x ?

The first derivative of x+c/x is 1-c/(x^2)

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\frac{d}{d x} (x + \frac{c}{x})

1 - \frac{c}{x ^{2}}

Solution steps

\frac{d}{d x} (x + \frac{c}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{c}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{c}{x}) = - \frac{c}{x ^{2}}

= 1 - \frac{c}{x ^{2}}

\frac{e ^{t^{2}} - 1}{t}

\int_{6}^{8} \frac{22}{( x - 6 ) ^{3}} d x

\int 7 x + 4 d x

x^{2} y + x + y

e^{- 2}

What is the derivative of x+c/x ?
The derivative of x+c/x is 1-c/(x^2)
What is the first derivative of x+c/x ?
The first derivative of x+c/x is 1-c/(x^2)