What is the integral from 0 to pi/6 of 9sec^2(x) ?

The integral from 0 to pi/6 of 9sec^2(x) is 3sqrt(3)

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integral from 0 to pi/6 of 9sec^2(x)

\int_{0}^{\frac{π}{6}} 9 sec^{2} (x) d x

33

Decimal Notation

5.19615 \dots

Solution steps

\int_{0}^{\frac{π}{6}} 9 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{\frac{π}{6}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 9 [tan (x)]_{0}^{\frac{π}{6}}

Compute the boundaries:

\frac{1}{3}

= 9 \cdot \frac{1}{3}

Simplify

= 33

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What is the integral from 0 to pi/6 of 9sec^2(x) ?
The integral from 0 to pi/6 of 9sec^2(x) is 3sqrt(3)