What is the solution for e^y*((dy)/(dx)+1)=1 ?

The solution for e^y*((dy)/(dx)+1)=1 is y=ln(-e^{-x-c_{1}}+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

e^y*((dy)/(dx)+1)=1

e^{y} \cdot (\frac{d y}{d x} + 1) = 1

y = ln (- e^{- x - c_{1}} + 1)

Solution steps

e^{y} \cdot (\frac{d y}{d x} + 1) = 1

Solve separable ODE:

y = ln (- e^{- x - c_{1}} + 1)

y = ln (- e^{- x - c_{1}} + 1)

y^{^{''}} + 3 y^{^{'}} + 10 y = 0

(- 6, - 6), (- 5, 0)

\int 16 cos^{2} (x + 3) sin^{2} (x + 3) d x

\frac{d}{d x} (x^{3} + 5 x^{2} - x^{- 2} + 8)

x \to 2 + lim (\frac{4}{x - 2})

What is the solution for e^y*((dy)/(dx)+1)=1 ?
The solution for e^y*((dy)/(dx)+1)=1 is y=ln(-e^{-x-c_{1}}+1)