What is the derivative of f(x)=9sin(3x) ?

The derivative of f(x)=9sin(3x) is 27cos(3x)

What is the first derivative of f(x)=9sin(3x) ?

The first derivative of f(x)=9sin(3x) is 27cos(3x)

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derivative of

f (x) = 9 sin (3 x)

27 cos (3 x)

Solution steps

\frac{d}{d x} (9 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 9 cos (3 x) \cdot 3

Simplify

= 27 cos (3 x)

\frac{d}{d y} (x + y^{2})

\int x 2 - x^{2} - x^{2} d x

\frac{d y}{d x} = \frac{sec ( y )}{( x - 4 ) ^{2}}

\int 2 x e^{x^{2}} csc^{2} (e^{x^{2}}) d x

x y^{^{'}} = y + x^{2}

What is the derivative of f(x)=9sin(3x) ?
The derivative of f(x)=9sin(3x) is 27cos(3x)
What is the first derivative of f(x)=9sin(3x) ?
The first derivative of f(x)=9sin(3x) is 27cos(3x)