What is the integral of xcos^2(x)sin(x) ?

The integral of xcos^2(x)sin(x) is -1/3 xcos^3(x)+1/3 (sin(x)-1/3 sin^3(x))+C

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integral of xcos^2(x)sin(x)

\int x cos^{2} (x) sin (x) d x

- \frac{1}{3} x cos^{3} (x) + \frac{1}{3} (sin (x) - \frac{1}{3} sin^{3} (x)) + C

Solution steps

\int x cos^{2} (x) sin (x) d x

Apply Integration By Parts

: - \frac{1}{3} x cos^{3} (x) - \int - \frac{1}{3} cos^{3} (x) d x

= - \frac{1}{3} x cos^{3} (x) - \int - \frac{1}{3} cos^{3} (x) d x

\int - \frac{1}{3} cos^{3} (x) d x = - \frac{1}{3} (sin (x) - \frac{sin ^{3} ( x )}{3})

= - \frac{1}{3} x cos^{3} (x) - (- \frac{1}{3} (sin (x) - \frac{sin ^{3} ( x )}{3}))

Simplify

- \frac{1}{3} x cos^{3} (x) - (- \frac{1}{3} (sin (x) - \frac{sin ^{3} ( x )}{3})) : - \frac{1}{3} x cos^{3} (x) + \frac{1}{3} (sin (x) - \frac{1}{3} sin^{3} (x))

= - \frac{1}{3} x cos^{3} (x) + \frac{1}{3} (sin (x) - \frac{1}{3} sin^{3} (x))

Add a constant to the solution

= - \frac{1}{3} x cos^{3} (x) + \frac{1}{3} (sin (x) - \frac{1}{3} sin^{3} (x)) + C

f (x) = x^{2} - 1, (- 2, 3)

x \to 2 lim (\frac{3}{2 - x})

\int (3 t + t^{2}) sin (3 t) d t

\int ln (1 + t^{2}) d t

\int \frac{tan ^{3} ( ln ( x ) )}{3 x} d x

What is the integral of xcos^2(x)sin(x) ?
The integral of xcos^2(x)sin(x) is -1/3 xcos^3(x)+1/3 (sin(x)-1/3 sin^3(x))+C