What is the derivative of 6sec(x)tan(x) ?

The derivative of 6sec(x)tan(x) is 6(-sec(x)+2sec^3(x))

What is the first derivative of 6sec(x)tan(x) ?

The first derivative of 6sec(x)tan(x) is 6(-sec(x)+2sec^3(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

6 sec (x) tan (x)

6 (- sec (x) + 2 sec^{3} (x))

Solution steps

\frac{d}{d x} (6 sec (x) tan (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (sec (x) tan (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sec (x), g = tan (x)

= 6 (\frac{d}{d x} (sec (x)) tan (x) + \frac{d}{d x} (tan (x)) sec (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 6 (sec (x) tan (x) tan (x) + sec^{2} (x) sec (x))

Simplify

6 (sec (x) tan (x) tan (x) + sec^{2} (x) sec (x)) : 6 (- sec (x) + 2 sec^{3} (x))

= 6 (- sec (x) + 2 sec^{3} (x))

n = 3 \sum \infty \frac{6}{n ( n - 2 )}

\frac{x ^{2} - 7 x + 3}{x ^{2} + 7}

y^{^{''}} + 4 y^{^{'}} + 5 y = 15 x + 5 e^{- x}

\frac{d}{d x} (e^{(x + y)^{2}})

x \to 4 + lim (- 3)

What is the derivative of 6sec(x)tan(x) ?
The derivative of 6sec(x)tan(x) is 6(-sec(x)+2sec^3(x))
What is the first derivative of 6sec(x)tan(x) ?
The first derivative of 6sec(x)tan(x) is 6(-sec(x)+2sec^3(x))