What is the tangent of f(x)=(2x)/(x^2+1),1,\at x=1 ?

The tangent of f(x)=(2x)/(x^2+1),1,\at x=1 is y=1

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tangent of f(x)=(2x)/(x^2+1),1,\at x=1

tangent of

f (x) = \frac{2 x}{x ^{2} + 1}, 1, at x = 1

y = 1

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = \frac{2 x}{x ^{2} + 1} : \frac{df ( x )}{d x} = \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{2 x}{x ^{2} + 1}

x = 1 : m = 0

Find the line with slope m=

0

and passing through

(1, 1) : y = 1

y = 1

\frac{d}{d x} (cos^{2} (9 x) + sin^{2} (9 x))

\frac{d}{d t} (4 e^{t})

(- 4 - 4) (- 42)

\int 5 x^{2} e^{x} d x

What is the tangent of f(x)=(2x)/(x^2+1),1,\at x=1 ?
The tangent of f(x)=(2x)/(x^2+1),1,\at x=1 is y=1