What is the derivative of 2sin^3(x) ?

The derivative of 2sin^3(x) is 6sin^2(x)cos(x)

What is the first derivative of 2sin^3(x) ?

The first derivative of 2sin^3(x) is 6sin^2(x)cos(x)

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\frac{d}{d x} (2 sin^{3} (x))

6 sin^{2} (x) cos (x)

Solution steps

\frac{d}{d x} (2 sin^{3} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin^{3} (x))

Apply the chain rule:

3 (sin (x))^{2} \frac{d}{d x} (sin (x))

= 3 (sin (x))^{2} \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= 2 \cdot 3 (sin (x))^{2} cos (x)

Simplify

= 6 sin^{2} (x) cos (x)

\int_{- 2}^{3} x^{2} - 4 d x

\int \frac{- 3}{y} d y

18 e^{t}

f (x) = \frac{3}{x}, at x = 4

\frac{d x}{d t} = x e^{t} + 3 e^{t} + x - 3

What is the derivative of 2sin^3(x) ?
The derivative of 2sin^3(x) is 6sin^2(x)cos(x)
What is the first derivative of 2sin^3(x) ?
The first derivative of 2sin^3(x) is 6sin^2(x)cos(x)