What is the solution for (dy)/(dt)=y(3-y),y(0)=4 ?

The solution for (dy)/(dt)=y(3-y),y(0)=4 is y=(12e^{3t})/(-1+4e^{3t)}

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(dy)/(dt)=y(3-y),y(0)=4

\frac{d y}{d t} = y (3 - y), y (0) = 4

y = \frac{12 e ^{3 t}}{- 1 + 4 e ^{3 t}}

Solution steps

\frac{d y}{d t} = y (3 - y)

Solve Bernoulli ODE:

y = \frac{12 e ^{3 t}}{- 1 + 4 e ^{3 t}}

y = \frac{12 e ^{3 t}}{- 1 + 4 e ^{3 t}}

\frac{s}{s ^{2} - \frac{1}{s}}

2 e^{t} + 5

\int 1 + 2 x^{2} + x^{4} d x

\frac{1}{x + 4}, 2

3 e^{\frac{1}{x}}

What is the solution for (dy)/(dt)=y(3-y),y(0)=4 ?
The solution for (dy)/(dt)=y(3-y),y(0)=4 is y=(12e^{3t})/(-1+4e^{3t)}