What is the limit as x approaches-3 of 2/(x^2-9) ?

The limit as x approaches-3 of 2/(x^2-9) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-3 of 2/(x^2-9)

x \to - 3 lim (\frac{2}{x ^{2} - 9})

diverges

Solution steps

x \to - 3 lim (\frac{2}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 3 + lim (\frac{2}{x ^{2} - 9}) = - \infty

x \to - 3 - lim (\frac{2}{x ^{2} - 9}) = \infty

= diverges

x y^{^{'}} = 2 x^{2} + y

\frac{d y}{d x} = 3 y^{2}

\int \frac{- 1}{y} d y

n \to \infty lim (∣ an ∣)

k = 1 \sum \infty \frac{1}{4 ^{k + 1}}

What is the limit as x approaches-3 of 2/(x^2-9) ?
The limit as x approaches-3 of 2/(x^2-9) is diverges