What is (\partial)/(\partial x)(x^2y^5) ?

The answer to (\partial)/(\partial x)(x^2y^5) is 2xy^5

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(\partial)/(\partial x)(x^2y^5)

\frac{\partial}{\partial x} (x^{2} y^{5})

2 x y^{5}

Solution steps

\frac{\partial}{\partial x} (x^{2} y^{5})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{5} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{5} \cdot 2 x^{2 - 1}

Simplify

= 2 x y^{5}

- 5 x^{2} y + y^{^{'}} = 5 x^{2}

\int ((sec (x))^{2} - csc (x) cot (x)) d x

x \to 0 lim (\frac{x}{x})

\int sin (x) \cdot sin (3 x) d x

\int 2 cos^{2} (2 x) d x

What is (\partial)/(\partial x)(x^2y^5) ?
The answer to (\partial)/(\partial x)(x^2y^5) is 2xy^5