What is the integral from 0 to infinity of 1/(x^2) ?

The integral from 0 to infinity of 1/(x^2) is diverges

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integral from 0 to infinity of 1/(x^2)

\int_{0}^{\infty} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{2}} d x = - \frac{1}{x} + C

Compute the boundaries:

\int_{0}^{\infty} \frac{1}{x ^{2}} d x =

diverges

= diverges

\int \frac{2 x + 1}{( x ^{2} + 6 x + 10 ) ( x + 1 )} d x

x \to - 6 lim (\frac{x ^{2} - 8}{6 - x})

\int_{- 2}^{2} (- x^{2} + 4)^{2} d x

x \to 0 lim (x cos (x))

f (x) = x^{2} + 2, (- 5, 27)

What is the integral from 0 to infinity of 1/(x^2) ?
The integral from 0 to infinity of 1/(x^2) is diverges