What is the derivative of f(x)= 1/(x+1) ?

The derivative of f(x)= 1/(x+1) is -1/((x+1)^2)

What is the first derivative of f(x)= 1/(x+1) ?

The first derivative of f(x)= 1/(x+1) is -1/((x+1)^2)

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derivative of

f (x) = \frac{1}{x + 1}

- \frac{1}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= - \frac{1}{( x + 1 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 1 ) ^{2}}

f (x) = x^{2} + 4, (- 4, 20)

\frac{d}{d u} (2 uv)

\frac{d}{d x} (ln ∣ coth (5 x) ∣)

y^{^{'}} + e^{y} t = e^{y} sin (t)

\frac{\partial}{\partial x} ((ln (x))^{2})

What is the derivative of f(x)= 1/(x+1) ?
The derivative of f(x)= 1/(x+1) is -1/((x+1)^2)
What is the first derivative of f(x)= 1/(x+1) ?
The first derivative of f(x)= 1/(x+1) is -1/((x+1)^2)