What is the first d/(dj)(12i+15j) ?

The first d/(dj)(12i+15j) is 15

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d/(dj)(12i+15j)

\frac{d}{d j} (12 i + 15 j)

15

Solution steps

\frac{d}{d j} (12 i + 15 j)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d j} (12 i) + \frac{d}{d j} (15 j)

\frac{d}{d j} (12 i) = 0

\frac{d}{d j} (15 j) = 15

= 0 + 15

Simplify

= 15

f (x) = 2 x^{2} + 5 x - 1, at x = - 3

\frac{d}{d x} ((4 x^{2} + 5) (5 x + 2)^{4})

\frac{d}{d t} ((t - 1)^{2})

\frac{d}{d x} (3^{c o s (x)})

\int \frac{5}{7 + 5 x} d x