What is the derivative of x^2+Ax+B ?

The derivative of x^2+Ax+B is 2x+A

What is the first derivative of x^2+Ax+B ?

The first derivative of x^2+Ax+B is 2x+A

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2} + A x + B)

2 x + A

Solution steps

\frac{d}{d x} (x^{2} + A x + B)

Treat

A, B

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (A x) + \frac{d B}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (A x) = A

\frac{d B}{d x} = 0

= 2 x + A + 0

Simplify

= 2 x + A

\int 2 tan^{3} (\frac{x}{4}) d x

n \to \infty lim ((1 + \frac{3}{n})^{- n^{2}})

\int 4 x e^{4 x} d x

x \to 0 lim (\frac{( tan ( x ) )}{x})

\frac{d}{d t} (e^{2 t s i n (2 t)})

What is the derivative of x^2+Ax+B ?
The derivative of x^2+Ax+B is 2x+A
What is the first derivative of x^2+Ax+B ?
The first derivative of x^2+Ax+B is 2x+A