What is the tangent of f(x)=-2x^4+10x^2,\at x=-1 ?

The tangent of f(x)=-2x^4+10x^2,\at x=-1 is y=-12x-4

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tangent of f(x)=-2x^4+10x^2,\at x=-1

tangent of

f (x) = - 2 x^{4} + 10 x^{2}, at x = - 1

y = - 12 x - 4

Solution steps

Find the tangent point:

(- 1, 8)

Find the slope of

f (x) = - 2 x^{4} + 10 x^{2} : \frac{df ( x )}{d x} = - 8 x^{3} + 20 x

Compute the slope of

f (x) = - 2 x^{4} + 10 x^{2}

x = - 1 : m = - 12

Find the line with slope m=

- 12

and passing through

(- 1, 8) : y = - 12 x - 4

y = - 12 x - 4

\frac{d}{d x} (1 - \frac{2}{x ^{2}})

\int x^{100} + x^{99} d x

(x^{2} - y^{2}) d x + 2 x y d y = 0

\int_{0}^{1} t^{3} (3 + t^{4})^{3} d t

f (x) = 12 - x

What is the tangent of f(x)=-2x^4+10x^2,\at x=-1 ?
The tangent of f(x)=-2x^4+10x^2,\at x=-1 is y=-12x-4