What is (\partial)/(\partial y)(3x^5tan(y)-2y^3) ?

The answer to (\partial)/(\partial y)(3x^5tan(y)-2y^3) is 3x^5sec^2(y)-6y^2

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(\partial)/(\partial y)(3x^5tan(y)-2y^3)

\frac{\partial}{\partial y} (3 x^{5} tan (y) - 2 y^{3})

3 x^{5} sec^{2} (y) - 6 y^{2}

Solution steps

\frac{\partial}{\partial y} (3 x^{5} tan (y) - 2 y^{3})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{5} tan (y)) - \frac{\partial}{\partial y} (2 y^{3})

\frac{\partial}{\partial y} (3 x^{5} tan (y)) = 3 x^{5} sec^{2} (y)

\frac{\partial}{\partial y} (2 y^{3}) = 6 y^{2}

= 3 x^{5} sec^{2} (y) - 6 y^{2}

\int_{1.5}^{2} cos (\frac{π x}{3}) d x

y^{^{'}} + y t = 6 cos (5 t)

sin (9 x)

\frac{d}{d x} ((a + \frac{b}{x ^{2}})^{3})

sin (x) ln (x)

What is (\partial)/(\partial y)(3x^5tan(y)-2y^3) ?
The answer to (\partial)/(\partial y)(3x^5tan(y)-2y^3) is 3x^5sec^2(y)-6y^2