What is the derivative of arcsec(2x+2) ?

The derivative of arcsec(2x+2) is 2/(sqrt((2x+2)^2)\sqrt{4x^2+8x+3)}

What is the first derivative of arcsec(2x+2) ?

The first derivative of arcsec(2x+2) is 2/(sqrt((2x+2)^2)\sqrt{4x^2+8x+3)}

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derivative of

arcsec (2 x + 2)

\frac{2}{( 2 x + 2 ) ^{2} 4 x ^{2} + 8 x + 3}

Solution steps

\frac{d}{d x} (arcsec (2 x + 2))

Apply the chain rule:

\frac{1}{( 2 x + 2 ) ^{2} ( 2 x + 2 ) ^{2} - 1} \frac{d}{d x} (2 x + 2)

= \frac{1}{( 2 x + 2 ) ^{2} ( 2 x + 2 ) ^{2} - 1} \frac{d}{d x} (2 x + 2)

\frac{d}{d x} (2 x + 2) = 2

= \frac{1}{( 2 x + 2 ) ^{2} ( 2 x + 2 ) ^{2} - 1} \cdot 2

Simplify

\frac{1}{( 2 x + 2 ) ^{2} ( 2 x + 2 ) ^{2} - 1} \cdot 2 : \frac{2}{( 2 x + 2 ) ^{2} 4 x ^{2} + 8 x + 3}

= \frac{2}{( 2 x + 2 ) ^{2} 4 x ^{2} + 8 x + 3}

\int 8 sin^{4} (x) cos^{2} (x) d x

\int e^{(2 x + 1)} d x

x y^{^{'}} - y - 3 = 0

x \to 0 lim (\frac{2 tan ( x )}{x})

\int \frac{3}{1 + 3 x} d x

What is the derivative of arcsec(2x+2) ?
The derivative of arcsec(2x+2) is 2/(sqrt((2x+2)^2)\sqrt{4x^2+8x+3)}
What is the first derivative of arcsec(2x+2) ?
The first derivative of arcsec(2x+2) is 2/(sqrt((2x+2)^2)\sqrt{4x^2+8x+3)}