What is the integral of 1/(3+25x^2) ?

The integral of 1/(3+25x^2) is 1/(5sqrt(3))arctan(5/(sqrt(3))x)+C

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integral of 1/(3+25x^2)

\int \frac{1}{3 + 25 x ^{2}} d x

\frac{1}{5 3} arctan (\frac{5}{3} x) + C

Solution steps

\int \frac{1}{3 + 25 x ^{2}} d x

Apply Integral Substitution

= \int \frac{1}{5 3 ( 1 + u ^{2} )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5 3} \cdot \int \frac{1}{1 + u ^{2}} d u

Use the common integral:

\int \frac{1}{1 + u ^{2}} d u = arctan (u)

= \frac{1}{5 3} arctan (u)

Substitute back

u = \frac{5}{3} x

= \frac{1}{5 3} arctan (\frac{5}{3} x)

Add a constant to the solution

= \frac{1}{5 3} arctan (\frac{5}{3} x) + C

\int cot^{6} (x) d x

(- 7.6) (4.2)

\frac{d}{d t} (\frac{t}{t - 1})

\frac{d}{d x} (\frac{x ^{6}}{3 - x ^{5}})

What is the integral of 1/(3+25x^2) ?
The integral of 1/(3+25x^2) is 1/(5sqrt(3))arctan(5/(sqrt(3))x)+C