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Popular >

integral from 0 to 4 of 3t-8

Solution

\int_{0}^{4} 3 t - 8 d t

Solution

- 8

Solution steps

\int_{0}^{4} 3 t - 8 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 3 t d t - \int_{0}^{4} 8 d t

\int_{0}^{4} 3 t d t = 24

\int_{0}^{4} 8 d t = 32

= 24 - 32

Simplify

= - 8

Popular Examples

(dy)/(dx)+y=2xy^2ex

\frac{d y}{d x} + y = 2 x y^{2} e x

inverse oflaplace 1/(4s+1)inverse laplace

\frac{1}{4 s + 1}

derivative of (4x-x^2/(6-x))

\frac{d}{d x} (\frac{4 x - x ^{2}}{6 - x})

tangent of f(x)=sqrt((2x-6)/(x-1))tangent of

f (x) = \frac{2 x - 6}{x - 1}

(dy)/(dx)=y^{1/2}

\frac{d y}{d x} = y^{\frac{1}{2}}

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of 3t-8 ?
The integral from 0 to 4 of 3t-8 is -8