What is the derivative of x^2+9x ?

The derivative of x^2+9x is 2x+9

What is the first derivative of x^2+9x ?

The first derivative of x^2+9x is 2x+9

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\frac{d}{d x} (x^{2} + 9 x)

2 x + 9

Solution steps

\frac{d}{d x} (x^{2} + 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (9 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (9 x) = 9

= 2 x + 9

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