What is the tangent of f(x)= 5/x ,(-3,(-5/3)) ?

The tangent of f(x)= 5/x ,(-3,(-5/3)) is y=-5/9 x-10/3

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tangent of f(x)= 5/x ,(-3,(-5/3))

tangent of

f (x) = \frac{5}{x}, (- 3, (- \frac{5}{3}))

y = - \frac{5}{9} x - \frac{10}{3}

Solution steps

Find the slope of

f (x) = \frac{5}{x} : \frac{df ( x )}{d x} = - \frac{5}{x ^{2}}

Compute the slope of

f (x) = \frac{5}{x}

(- 3, (- \frac{5}{3})) : m = - \frac{5}{9}

Find the line with slope m=

- \frac{5}{9}

and passing through

(- 3, (- \frac{5}{3})) : y = - \frac{5}{9} x - \frac{10}{3}

y = - \frac{5}{9} x - \frac{10}{3}

\frac{d x}{d t} + 3 = 0

y = 4 + csc (t^{4})

y = (\frac{x - 1}{x ^{2} + x + 1})^{4}

y^{^{'}} + 2 x y = 2 x

\int 5 e^{x} 1 + e^{x} d x

What is the tangent of f(x)= 5/x ,(-3,(-5/3)) ?
The tangent of f(x)= 5/x ,(-3,(-5/3)) is y=-5/9 x-10/3