What is the sum from n=1 to infinity of 1/((2n-1)^6) ?

The sum from n=1 to infinity of 1/((2n-1)^6) is converges

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sum from n=1 to infinity of 1/((2n-1)^6)

n = 1 \sum \infty \frac{1}{( 2 n - 1 ) ^{6}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{( 2 n - 1 ) ^{6}}

Apply Series Integral Test:

converges

= converges

\int_{0}^{l n (3)} e^{2 x} d x

x \to 0 + lim (3 x^{\frac{x}{2}})

y = 3 x, y = 9 x^{2}

y^{^{''}} + 4 y = 9 e^{2 t} sin (2 t) + 5 t^{2}

sec (x)

What is the sum from n=1 to infinity of 1/((2n-1)^6) ?
The sum from n=1 to infinity of 1/((2n-1)^6) is converges