What is (\partial)/(\partial x)(-4x^2y-4x) ?

The answer to (\partial)/(\partial x)(-4x^2y-4x) is -8yx-4

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(\partial)/(\partial x)(-4x^2y-4x)

\frac{\partial}{\partial x} (- 4 x^{2} y - 4 x)

- 8 y x - 4

Solution steps

\frac{\partial}{\partial x} (- 4 x^{2} y - 4 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (4 x^{2} y) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x^{2} y) = 8 y x

\frac{\partial}{\partial x} (4 x) = 4

= - 8 y x - 4

\frac{d}{d x} (\frac{x ^{2} + 4 x + 8}{( x + 2 ) ^{2}})

f (x) = - x^{\frac{4}{3}}

\int_{- 1}^{1} (8 - 8 x^{2})^{2} d x

\frac{\partial}{\partial x} (y^{2} cos (x y))

\int a cos (x) d x

What is (\partial)/(\partial x)(-4x^2y-4x) ?
The answer to (\partial)/(\partial x)(-4x^2y-4x) is -8yx-4