What is the derivative of sqrt(2x^2+7) ?

The derivative of sqrt(2x^2+7) is (2x)/(sqrt(2x^2+7))

What is the first derivative of sqrt(2x^2+7) ?

The first derivative of sqrt(2x^2+7) is (2x)/(sqrt(2x^2+7))

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derivative of

2 x^{2} + 7

\frac{2 x}{2 x ^{2} + 7}

Solution steps

\frac{d}{d x} (2 x^{2} + 7)

Apply the chain rule:

\frac{1}{2 2 x ^{2} + 7} \frac{d}{d x} (2 x^{2} + 7)

= \frac{1}{2 2 x ^{2} + 7} \frac{d}{d x} (2 x^{2} + 7)

\frac{d}{d x} (2 x^{2} + 7) = 4 x

= \frac{1}{2 2 x ^{2} + 7} \cdot 4 x

Simplify

\frac{1}{2 2 x ^{2} + 7} \cdot 4 x : \frac{2 x}{2 x ^{2} + 7}

= \frac{2 x}{2 x ^{2} + 7}

y^{^{'}} - 2 y = - 1, y (0) = 3

(y - x) e^{x} + (1 + e^{x}) y^{^{'}} = 0

10 + \frac{50 t}{2 t ^{2} + 9}

x \to - 2 lim (\frac{1}{2})

\frac{- 3 e ^{6 - 3 s}}{( s - 2 ) ( s - 3 ) ( s + 2 )}

What is the derivative of sqrt(2x^2+7) ?
The derivative of sqrt(2x^2+7) is (2x)/(sqrt(2x^2+7))
What is the first derivative of sqrt(2x^2+7) ?
The first derivative of sqrt(2x^2+7) is (2x)/(sqrt(2x^2+7))