What is the derivative of-2pisin(4pix) ?

The derivative of-2pisin(4pix) is -8pi^2cos(4pix)

What is the first derivative of-2pisin(4pix) ?

The first derivative of-2pisin(4pix) is -8pi^2cos(4pix)

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derivative of

- 2 π sin (4 π x)

- 8 π^{2} cos (4 π x)

Solution steps

\frac{d}{d x} (- 2 π sin (4 π x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 π \frac{d}{d x} (sin (4 π x))

Apply the chain rule:

cos (4 π x) \frac{d}{d x} (4 π x)

= cos (4 π x) \frac{d}{d x} (4 π x)

\frac{d}{d x} (4 π x) = 4 π

= - 2 π cos (4 π x) \cdot 4 π

Simplify

- 2 π cos (4 π x) \cdot 4 π : - 8 π^{2} cos (4 π x)

= - 8 π^{2} cos (4 π x)

\frac{d}{d x} (230 - 8 x + 0.04 x^{2})

\frac{d}{d x} (\frac{csc ( x ) \cdot tan ( x )}{cos ( x )})

\frac{\partial}{\partial x} ((1 - x^{2} - y^{2})^{\frac{1}{2}})

x \to \frac{π}{2} + lim (\frac{9}{x} sec (x))

\frac{\partial}{\partial y} (e^{z} cos (y))

What is the derivative of-2pisin(4pix) ?
The derivative of-2pisin(4pix) is -8pi^2cos(4pix)
What is the first derivative of-2pisin(4pix) ?
The first derivative of-2pisin(4pix) is -8pi^2cos(4pix)