What is the integral from 1 to 2 of 1/(x^2) ?

The integral from 1 to 2 of 1/(x^2) is 1/2

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integral from 1 to 2 of 1/(x^2)

\int_{1}^{2} \frac{1}{x ^{2}} d x

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{1}^{2} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{2}

= [- \frac{1}{x}]_{1}^{2}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

\frac{d}{d x} (4 \cdot sin (x))

sin (x^{2}), \frac{π}{4}

n = 1 \sum \infty n \cdot (\frac{4}{5})^{n}

x \to 0 + lim (x (ln (x)))

4 x^{2} - 3 x + 2

What is the integral from 1 to 2 of 1/(x^2) ?
The integral from 1 to 2 of 1/(x^2) is 1/2