What is (\partial)/(\partial z)(2xz^2cos(y)) ?

The answer to (\partial)/(\partial z)(2xz^2cos(y)) is 4xzcos(y)

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(\partial)/(\partial z)(2xz^2cos(y))

\frac{\partial}{\partial z} (2 x z^{2} cos (y))

4 x z cos (y)

Solution steps

\frac{\partial}{\partial z} (2 x z^{2} cos (y))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x cos (y) \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x cos (y) \cdot 2 z^{2 - 1}

Simplify

= 4 x z cos (y)

x \to 0 lim (\frac{x ^{2}}{x + 1})

\int sin^{3} (x) cos^{16} (x) d x

y \to 0 lim (\frac{x ^{y} - 1}{y})

8 8 x^{2} + 5

x \to 0 - lim (\frac{4}{sin ( x )})

What is (\partial)/(\partial z)(2xz^2cos(y)) ?
The answer to (\partial)/(\partial z)(2xz^2cos(y)) is 4xzcos(y)