What is the integral of e^xsqrt(6-e^x) ?

The integral of e^xsqrt(6-e^x) is -2/3 (6-e^x)^{3/2}+C

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integral of e^xsqrt(6-e^x)

\int e^{x} 6 - e^{x} d x

- \frac{2}{3} (6 - e^{x})^{\frac{3}{2}} + C

Solution steps

\int e^{x} 6 - e^{x} d x

Apply u-substitution

: \int - u d u

= \int - u d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= - \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 6 - e^{x}

= - \frac{2}{3} (6 - e^{x})^{\frac{3}{2}}

Add a constant to the solution

= - \frac{2}{3} (6 - e^{x})^{\frac{3}{2}} + C

(3 x^{2})^{^{'}}

\int \frac{x ^{2}}{x ^{6} + 1} d x

\int \frac{20}{x + 5} d x

(2, 1), (8, 7)

(f (x))^{g (x)}

What is the integral of e^xsqrt(6-e^x) ?
The integral of e^xsqrt(6-e^x) is -2/3 (6-e^x)^{3/2}+C