What is (\partial)/(\partial x)(-3sin(3x)) ?

The answer to (\partial)/(\partial x)(-3sin(3x)) is -9cos(3x)

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(\partial)/(\partial x)(-3sin(3x))

\frac{\partial}{\partial x} (- 3 sin (3 x))

- 9 cos (3 x)

Solution steps

\frac{\partial}{\partial x} (- 3 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{\partial}{\partial x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{\partial}{\partial x} (3 x)

= cos (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= - 3 cos (3 x) \cdot 3

Simplify

= - 9 cos (3 x)

4 x - \frac{x ^{3}}{4}

\int - y sin (y) d y

\int (sin (π) x) d x

e^{\frac{1}{x - 9}}, 7

\frac{1}{( s + 1 ) ^{2} + 1}

What is (\partial)/(\partial x)(-3sin(3x)) ?
The answer to (\partial)/(\partial x)(-3sin(3x)) is -9cos(3x)