What is the derivative of f(x)=(x^2)/(1+x) ?

The derivative of f(x)=(x^2)/(1+x) is (2x+x^2)/((1+x)^2)

What is the first derivative of f(x)=(x^2)/(1+x) ?

The first derivative of f(x)=(x^2)/(1+x) is (2x+x^2)/((1+x)^2)

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derivative of

f (x) = \frac{x ^{2}}{1 + x}

\frac{2 x + x ^{2}}{( 1 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{1 + x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 1 + x ) - \frac{d}{d x} ( 1 + x ) x ^{2}}{( 1 + x ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1 + x) = 1

= \frac{2 x ( 1 + x ) - 1 \cdot x ^{2}}{( 1 + x ) ^{2}}

Simplify

\frac{2 x ( 1 + x ) - 1 \cdot x ^{2}}{( 1 + x ) ^{2}} : \frac{2 x + x ^{2}}{( 1 + x ) ^{2}}

= \frac{2 x + x ^{2}}{( 1 + x ) ^{2}}

y y^{^{'}} = x^{2}

\int a^{x} d x

x \to 1 lim (x^{2} + 2 x)

\frac{d}{d x} ((sin (3 x))^{4})

\int \frac{1}{2 - x} d x

What is the derivative of f(x)=(x^2)/(1+x) ?
The derivative of f(x)=(x^2)/(1+x) is (2x+x^2)/((1+x)^2)
What is the first derivative of f(x)=(x^2)/(1+x) ?
The first derivative of f(x)=(x^2)/(1+x) is (2x+x^2)/((1+x)^2)