What is the derivative of x=18.432tcos(1.44t^2) ?

The derivative of x=18.432tcos(1.44t^2) is 18.432(cos(1.44t^2)-2.88t^2sin(1.44t^2))

What is the first derivative of x=18.432tcos(1.44t^2) ?

The first derivative of x=18.432tcos(1.44t^2) is 18.432(cos(1.44t^2)-2.88t^2sin(1.44t^2))

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derivative of

x = 18.432 t cos (1.44 t^{2})

18.432 (cos (1.44 t^{2}) - 2.88 t^{2} sin (1.44 t^{2}))

Solution steps

\frac{d}{d t} (18.432 t cos (1.44 t^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 18.432 \frac{d}{d t} (t cos (1.44 t^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = cos (1.44 t^{2})

= 18.432 (\frac{d t}{d t} cos (1.44 t^{2}) + \frac{d}{d t} (cos (1.44 t^{2})) t)

\frac{d t}{d t} = 1

\frac{d}{d t} (cos (1.44 t^{2})) = - sin (1.44 t^{2}) \cdot 2.88 t

= 18.432 (1 \cdot cos (1.44 t^{2}) + (- sin (1.44 t^{2}) \cdot 2.88 t) t)

Simplify

18.432 (1 \cdot cos (1.44 t^{2}) + (- sin (1.44 t^{2}) \cdot 2.88 t) t) : 18.432 (cos (1.44 t^{2}) - 2.88 t^{2} sin (1.44 t^{2}))

= 18.432 (cos (1.44 t^{2}) - 2.88 t^{2} sin (1.44 t^{2}))

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\frac{d}{d y} (\frac{y}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}})

\int cos (x) - 5 sin (x) - 7 d x

\frac{d}{d t} (e^{2 t} + 2 e^{t} + 1)

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What is the derivative of x=18.432tcos(1.44t^2) ?
The derivative of x=18.432tcos(1.44t^2) is 18.432(cos(1.44t^2)-2.88t^2sin(1.44t^2))
What is the first derivative of x=18.432tcos(1.44t^2) ?
The first derivative of x=18.432tcos(1.44t^2) is 18.432(cos(1.44t^2)-2.88t^2sin(1.44t^2))