What is the y^'(x)=(9x^2)/(9y^2-11),y(11)=0 ?

The y^'(x)=(9x^2)/(9y^2-11),y(11)=0 is -(9x^2)/(11)

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y^'(x)=(9x^2)/(9y^2-11),y(11)=0

y^{^{'}} (x) = \frac{9 x ^{2}}{9 y ^{2} - 11}, y (11) = 0

- \frac{9 x ^{2}}{11}

Solution steps

\frac{9 x ^{2}}{9 y ^{2} - 11} = \frac{9 x ^{2}}{9 y ^{2} - 11}

Constant function results in a constant

y (11) = 0

= \frac{9 x ^{2}}{9 \cdot 0 ^{2} - 11}

Simplify

\frac{9 x ^{2}}{9 \cdot 0 ^{2} - 11} : - \frac{9 x ^{2}}{11}

= - \frac{9 x ^{2}}{11}

f (x) = 675 - 4.9 x^{2}

\frac{d}{d x} (7^{x^{3}})

2 y^{^{''}} - 3 y^{^{'}} + 4 y = 0

\frac{\partial}{\partial z} (- x^{3} yz e^{z})

\frac{d}{d x} (1000 e^{- \frac{x}{10}})

What is the y^'(x)=(9x^2)/(9y^2-11),y(11)=0 ?
The y^'(x)=(9x^2)/(9y^2-11),y(11)=0 is -(9x^2)/(11)