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Popular >

area y=x^2,[0,1]

Solution

area

y = x^{2}, [0, 1]

Solution

\frac{1}{3}

+1

Solution steps

Apply the area formula:

\int_{0}^{1} ∣ x ∣^{2} d x

Solve

\int_{0}^{1} ∣ x ∣^{2} d x : \frac{1}{3}

The area is:

= \frac{1}{3}

Popular Examples

25y^{''}+15y^'-4y=0

25 y^{^{''}} + 15 y^{^{'}} - 4 y = 0

derivative of-x-3 derivative of

- x - 3

integral of (6x+1)

\int (6 x + 1) d x

y = ln (ln (2 x))

integral from 0 to pi/2 of 8sin^2(3x)

\int_{0}^{\frac{π}{2}} 8 sin^{2} (3 x) d x

Frequently Asked Questions (FAQ)

What is area y=x^2,[0,1] ?
The answer to area y=x^2,[0,1] is 1/3