What is the integral from 4 to 9 of 3sqrt(x) ?

The integral from 4 to 9 of 3sqrt(x) is 38

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integral from 4 to 9 of 3sqrt(x)

\int_{4}^{9} 3 x d x

38

Solution steps

\int_{4}^{9} 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{4}^{9} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

= 3 [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

Compute the boundaries:

\frac{38}{3}

= 3 \cdot \frac{38}{3}

Simplify

= 38

\int 3 x^{3} cos (x) d x

f (x) = x^{2} - 5 x + 5, at x = 0

\int x^{2} + 4 x d x

y^{^{''}} + y = - sin (2 x)

\frac{d}{d y} (arctan (\frac{x}{y}))

What is the integral from 4 to 9 of 3sqrt(x) ?
The integral from 4 to 9 of 3sqrt(x) is 38