What is the slope of 6x^2+3xy+y^2=16,(1,2) ?

The slope of 6x^2+3xy+y^2=16,(1,2) is -18/7

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slope of 6x^2+3xy+y^2=16,(1,2)

slope

6 x^{2} + 3 x y + y^{2} = 16, (1, 2)

- \frac{18}{7}

Solution steps

6 x^{2} + 3 x y + y^{2} = 16

Use implicit differentiation to find the slope of

6 x^{2} + 3 x y + y^{2} = 16

Implicit Derivative

\frac{d y}{d x}

6 x^{2} + 3 x y + y^{2} = 16 : \frac{- 12 x - 3 y}{3 x + 2 y}

\frac{- 12 x - 3 y}{3 x + 2 y}

Find the slope at

(1, 2) : - \frac{18}{7}

- \frac{18}{7}

\int_{1}^{8} π (x - 1)^{2} d x

\frac{d}{d x} (2 d x)

\int \frac{1}{e ^{2 x} + 4} d x

y^{^{''}} + 4 y^{^{'}} + 3 y = e^{- x}

\int (cos (x)) e^{s i n (x)} d x

What is the slope of 6x^2+3xy+y^2=16,(1,2) ?
The slope of 6x^2+3xy+y^2=16,(1,2) is -18/7