What is the derivative of (2x^2-3^3) ?

The derivative of (2x^2-3^3) is 12x(2x^2-3)^2

What is the first derivative of (2x^2-3^3) ?

The first derivative of (2x^2-3^3) is 12x(2x^2-3)^2

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\frac{d}{d x} ((2 x^{2} - 3)^{3})

12 x (2 x^{2} - 3)^{2}

Solution steps

\frac{d}{d x} ((2 x^{2} - 3)^{3})

Apply the chain rule:

3 (2 x^{2} - 3)^{2} \frac{d}{d x} (2 x^{2} - 3)

= 3 (2 x^{2} - 3)^{2} \frac{d}{d x} (2 x^{2} - 3)

\frac{d}{d x} (2 x^{2} - 3) = 4 x

= 3 (2 x^{2} - 3)^{2} \cdot 4 x

Simplify

= 12 x (2 x^{2} - 3)^{2}

y = \frac{2}{( 4 x - 3 ) ^{\frac{1}{2}}}

f (x) = (1 + 2 x)^{2}

(4 x + 5)^{3}

x \to \frac{π}{2} lim (- cot (2 x))

\frac{d}{d x} (12 tan (cosh (e^{4 x})))

What is the derivative of (2x^2-3^3) ?
The derivative of (2x^2-3^3) is 12x(2x^2-3)^2
What is the first derivative of (2x^2-3^3) ?
The first derivative of (2x^2-3^3) is 12x(2x^2-3)^2