What is the solution for cos^2(x)sin(x)y^'+cos^3(x)y=2 ?

The solution for cos^2(x)sin(x)y^'+cos^3(x)y=2 is y=(2tan(x))/(sin(x))+(c_{1})/(sin(x))

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cos^2(x)sin(x)y^'+cos^3(x)y=2

cos^{2} (x) sin (x) y^{^{'}} + cos^{3} (x) y = 2

y = \frac{2 tan ( x )}{sin ( x )} + \frac{c _{1}}{sin ( x )}

Solution steps

cos^{2} (x) sin (x) y^{'} (x) + cos^{3} (x) y = 2

Solve linear ODE:

y = \frac{2 tan ( x )}{sin ( x )} + \frac{c _{1}}{sin ( x )}

y = \frac{2 tan ( x )}{sin ( x )} + \frac{c _{1}}{sin ( x )}

\int_{0}^{3} 2 π x (3 - x) d x

\frac{\partial}{\partial x} (4 ln (x y) - (x + y)^{2} + 5)

f (x) = \frac{( 3 x + 2 )}{( 3 x - 2 )}

\int (x ln (x)) d x

\int (x + 1) y^{2} \cdot sin (\frac{x y}{3}) d x

What is the solution for cos^2(x)sin(x)y^'+cos^3(x)y=2 ?
The solution for cos^2(x)sin(x)y^'+cos^3(x)y=2 is y=(2tan(x))/(sin(x))+(c_{1})/(sin(x))