What is the derivative of 1/(6x^2) ?

The derivative of 1/(6x^2) is -1/(3x^3)

What is the first derivative of 1/(6x^2) ?

The first derivative of 1/(6x^2) is -1/(3x^3)

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\frac{d}{d x} (\frac{1}{6 x ^{2}})

- \frac{1}{3 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{6 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{6} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{6} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{6} (- 2 x^{- 2 - 1})

Simplify

\frac{1}{6} (- 2 x^{- 2 - 1}) : - \frac{1}{3 x ^{3}}

= - \frac{1}{3 x ^{3}}

\int \frac{1}{( x ^{2} - 4 x + 4 ) ( x ^{2} - 5 x + 6 )} d x

\int \frac{1}{3 + 2 x} d x

\int - 1 sin^{3} (x) cos^{2} (x) d x

\int x (tan (x))^{2} d x

x^{2} + 1, 3 - x, x = 0

What is the derivative of 1/(6x^2) ?
The derivative of 1/(6x^2) is -1/(3x^3)
What is the first derivative of 1/(6x^2) ?
The first derivative of 1/(6x^2) is -1/(3x^3)