en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x^2+1,3-x,x=0

Solution

area

x^{2} + 1, 3 - x, x = 0

Solution

\frac{9}{2}

+1

Solution steps

Apply the area formula:

\int_{- 2}^{1} x^{2} + 1 - (3 - x) d x

Solve

\int_{- 2}^{1} x^{2} + 1 - (3 - x) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

Popular Examples

derivative of ((tan(x)/x)^2)

\frac{d}{d x} ((\frac{tan ( x )}{x})^{2})

integral of (x-6)/((x+3)^2+36)

\int \frac{x - 6}{( x + 3 ) ^{2} + 36} d x

sum from n=1 to infinity of nln(2)

n = 1 \sum \infty n ln (2)

integral of sin^2(v)cos^3(v)

\int sin^{2} (v) cos^{3} (v) d v

derivative of (sin(x)(cos(x)))

\frac{d}{d x} ((sin (x)) (cos (x)))

Frequently Asked Questions (FAQ)

What is area x^2+1,3-x,x=0 ?
The answer to area x^2+1,3-x,x=0 is 9/2