What is the d/(dθ)(8sin(θ)) ?

The d/(dθ)(8sin(θ)) is 8cos(θ)

What is the first d/(dθ)(8sin(θ)) ?

The first d/(dθ)(8sin(θ)) is 8cos(θ)

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\frac{d}{d θ} (8 sin (θ))

8 cos (θ)

Solution steps

\frac{d}{d θ} (8 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 8 cos (θ)

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\frac{\partial}{\partial x} (\frac{4 y}{x ^{5}})

\frac{d}{d x} (ln (16 - 4 x^{2} - 4 y^{2} - z^{2}))

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x \to 0 - lim (\frac{1}{sin ( x )})