derivative y=-x^3+2x

פתרון

derivative of

y = - x^{3} + 2 x

- 3 x^{2} + 2

צעדי פתרון

\frac{d}{d x} (- x^{3} + 2 x)

(f \pm g)^{'} = f^{'} \pm g^{'}

:השתמש בחוק החיבור

= - \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

= - 3 x^{2} + 2

sin (\frac{π}{6} + x)

\frac{d}{d x} (1 - e^{- 4 x})

\int 1^{\frac{1}{2}}

\frac{- x ^{2} - 4 x}{( x ^{2} - x - 2 ) ^{2}}

n = 1 \sum \infty 4 \cdot 0. 3^{n}