What is (\partial)/(\partial z)(e^x+z^2) ?

The answer to (\partial)/(\partial z)(e^x+z^2) is 2z

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(\partial)/(\partial z)(e^x+z^2)

\frac{\partial}{\partial z} (e^{x} + z^{2})

2 z

Solution steps

\frac{\partial}{\partial z} (e^{x} + z^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (e^{x}) + \frac{\partial}{\partial z} (z^{2})

\frac{\partial}{\partial z} (e^{x}) = 0

\frac{\partial}{\partial z} (z^{2}) = 2 z

= 0 + 2 z

Simplify

= 2 z

y = - 588145 x 2 + 54170 x - 340.33, 0, 0.085

\int sin^{5} (10 x) d x

\frac{d}{d θ} (3 - 3 sin (θ))

\int_{1}^{2} (\frac{1}{x ^{2}}) d x

\int - \frac{1}{1 + 2 x} d x

What is (\partial)/(\partial z)(e^x+z^2) ?
The answer to (\partial)/(\partial z)(e^x+z^2) is 2z