What is (\partial)/(\partial x)(1-3/y+x) ?

The answer to (\partial)/(\partial x)(1-3/y+x) is 1

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(\partial)/(\partial x)(1-3/y+x)

\frac{\partial}{\partial x} (1 - \frac{3}{y} + x)

1

Solution steps

\frac{\partial}{\partial x} (1 - \frac{3}{y} + x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) - \frac{\partial}{\partial x} (\frac{3}{y}) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (\frac{3}{y}) = 0

\frac{\partial}{\partial x} (x) = 1

= 0 - 0 + 1

Simplify

= 1

\int_{1}^{8} 1 + 3 x d x

\frac{d y}{d x} = ka e^{- k x} - b y

\frac{s}{( s ^{2} - 1 ^{2} ) ^{2}}

n = 1 \sum \infty \frac{1}{n ^{3} - n}

y = \frac{3 x}{e ^{x}}

What is (\partial)/(\partial x)(1-3/y+x) ?
The answer to (\partial)/(\partial x)(1-3/y+x) is 1