What is the integral from-3 to 0 of 1/(sqrt(9-x^2)) ?

The integral from-3 to 0 of 1/(sqrt(9-x^2)) is pi/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 0 of 1/(sqrt(9-x^2))

\int_{- 3}^{0} \frac{1}{9 - x ^{2}} d x

\frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

\int_{- 3}^{0} \frac{1}{9 - x ^{2}} d x

Apply Trigonometric Substitution

: \int_{- \frac{π}{2}}^{0} 1 d u

= \int_{- \frac{π}{2}}^{0} 1 d u

Integral of a constant:

\int a d x = a x

= [1 \cdot u]_{- \frac{π}{2}}^{0}

Simplify

= [u]_{- \frac{π}{2}}^{0}

Compute the boundaries:

\frac{π}{2}

= \frac{π}{2}

\frac{\partial}{\partial y} (e^{x y} sin (y))

\int_{0}^{20} cos (π x) d x

\int ln (x - 5) d x

\frac{d}{d x} ((sin (x))^{3})

x \to 0 lim (\frac{x ^{2}}{x})

What is the integral from-3 to 0 of 1/(sqrt(9-x^2)) ?
The integral from-3 to 0 of 1/(sqrt(9-x^2)) is pi/2