What is the derivative of 15x-0.4x^2-80 ?

The derivative of 15x-0.4x^2-80 is -0.8x+15

What is the first derivative of 15x-0.4x^2-80 ?

The first derivative of 15x-0.4x^2-80 is -0.8x+15

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derivative of

15 x - 0.4 x^{2} - 80

- 0.8 x + 15

Solution steps

\frac{d}{d x} (15 x - 0.4 x^{2} - 80)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (15 x) - \frac{d}{d x} (0.4 x^{2}) - \frac{d}{d x} (80)

\frac{d}{d x} (15 x) = 15

\frac{d}{d x} (0.4 x^{2}) = 0.8 x

\frac{d}{d x} (80) = 0

= 15 - 0.8 x - 0

Simplify

= - 0.8 x + 15

\frac{\partial}{\partial x} (cos (5 x + 9 y + 7 z))

\int \frac{1}{x ^{2} - 2 x + 4} d x

f (x) = cos^{6} (x)

\frac{\partial}{\partial x} (\frac{y}{( 1 + x ) ^{2}})

x \to - 6 lim (- 9 x)

What is the derivative of 15x-0.4x^2-80 ?
The derivative of 15x-0.4x^2-80 is -0.8x+15
What is the first derivative of 15x-0.4x^2-80 ?
The first derivative of 15x-0.4x^2-80 is -0.8x+15