What is (\partial)/(\partial y)(2y^2x-3) ?

The answer to (\partial)/(\partial y)(2y^2x-3) is 4yx

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(\partial)/(\partial y)(2y^2x-3)

\frac{\partial}{\partial y} (2 y^{2} x - 3)

4 y x

Solution steps

\frac{\partial}{\partial y} (2 y^{2} x - 3)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 y^{2} x) - \frac{\partial}{\partial y} (3)

\frac{\partial}{\partial y} (2 y^{2} x) = 4 x y

\frac{\partial}{\partial y} (3) = 0

= 4 x y - 0

Simplify

= 4 y x

\int x (x + 1)^{3} d x

\frac{d}{d x} (0.5 e^{x - 1})

x \frac{d y}{d x} + y = x y^{2}

\frac{d}{d x} (2 x^{3} - 4)

\frac{\partial}{\partial x} (3 x - 4 t)

What is (\partial)/(\partial y)(2y^2x-3) ?
The answer to (\partial)/(\partial y)(2y^2x-3) is 4yx