What is the solution for 4y^{''}+11y=0 ?

The solution for 4y^{''}+11y=0 is y=c_{1}cos((sqrt(11)t)/2)+c_{2}sin((sqrt(11)t)/2)

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4y^{''}+11y=0

4 y^{^{''}} + 11 y = 0

y = c_{1} cos (\frac{11 t}{2}) + c_{2} sin (\frac{11 t}{2})

Solution steps

4 y^{''} (t) + 11 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{11 t}{2}) + c_{2} sin (\frac{11 t}{2})

y = c_{1} cos (\frac{11 t}{2}) + c_{2} sin (\frac{11 t}{2})

\int θ arcsec (6 θ) d θ

\int (\frac{1}{2})^{r^{2}} d θ

f (x) = \frac{14}{( 1 + e - x ) , at ( 0 , 7 )}

\frac{d}{d x} (ln (\frac{x ^{\frac{4}{3}} cos ( x )}{7 x + 6}))

y = f (x), at x = 1

What is the solution for 4y^{''}+11y=0 ?
The solution for 4y^{''}+11y=0 is y=c_{1}cos((sqrt(11)t)/2)+c_{2}sin((sqrt(11)t)/2)