What is the integral from 0 to 1 of (37)/(x^5) ?

The integral from 0 to 1 of (37)/(x^5) is diverges

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integral from 0 to 1 of (37)/(x^5)

\int_{0}^{1} \frac{37}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{37}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 37 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 37 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

2 y^{^{''}} + 8 y^{^{'}} + 80 y - 60 cos (8 t) = 0

\int \frac{5 ^{x}}{x} d x

\frac{d y}{d x}, x y = 20

\frac{d}{d x} (\frac{4 x}{3 ( x ^{2} - 4 ) ^{\frac{1}{3}}})

\frac{d}{d x} (\frac{sin ( x )}{2 cos ^{2} ( x )})

What is the integral from 0 to 1 of (37)/(x^5) ?
The integral from 0 to 1 of (37)/(x^5) is diverges